#integral word problem help
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an infinitesimal of volume is $\dd{V}=r(t)\dd{t}$, so $V=\int\dd{V}=\int_0^{60}r(t)\dd{t}$ since it wants the 1st hour
Omegabet_
i set it all up like that and i keep coming up with 6037 Litres
$110\int_0^{60}e^{-0.01t}\dd{t}=\frac{-110}{0.01}[e^{-0.01t}]_0^{60}$
Omegabet_
idk how you got 6037 since you never posted work
just use a calculator properly for approximating the number ig?
e^0 isnt 0
re your last line
got it