How do I do this?

[knotty agate]

"Find the domain, and sketch the graph of the function."

[errant blaze]

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[last girder]

what do you have so far

[knotty agate]

Nothing. I forgot how to do these.

[last girder]

ok

in what scenarios would |x| < 1

[knotty agate]

x would have to be 0

[last girder]

not necessarily

|0.5| < 1 also

[knotty agate]

oh right

so any number between 0 & .9

[last girder]

that is also not necessarily true

because you have absolute value

[knotty agate]

oh right

also between 0 & -.9

[last girder]

the way you write it is -1 < x < 1

now, what values of x is this defined for

in other words what values of x can satisfy one of the "if" lines

(i would advise against using this .9 notation, because that leaves out .95 etc, you also can't say between 0 and .9999999... because that is 1)

[last girder]

anyway once you do that i assume you know how to graph the 3 lines shown so just graph that line but only where x satisfies the condition, for example, draw y = -1 where x <= -1

[knotty agate]

oh

[knotty agate]

?

[last girder]

what confuses you

do you know how to graph y = 3x + 2

[knotty agate]

yeah

[last girder]

ok so just graph that in the area where -1 < x < 1

[knotty agate]

idk how to do that

[last girder]

huh

idk how to explain how to do that

that's this part of the plane

[knotty agate]

ik how to graph it but idk how to graph it "in the area where -1 < x < 1" respectfully

[knotty agate]

oh ok

@last girder ok i graphed it

[last girder]

yay

[knotty agate]

what's next

[last girder]

there are no arrows

on the 3x + 2

because it stops there

[knotty agate]

oh

all right

[last girder]

so you just do that for the other 2 parts of the function as well

[knotty agate]

okay

@last girder for the third one i don't include the y intercept right?

[last girder]

yes you only include the part to the left of the middle line

[knotty agate]

huh?

1 sec

this is what i have so far for the 3rd one:

[last girder]

well draw them on the same graph

and connect the dots

[knotty agate]

oh..

all right

@last girder this final product is correct right?

[last girder]

almost

you have nothing graphed in the -1 to 0 section

but remember -1 < x < 1 has the 3x + 2

[knotty agate]

oh right

[knotty agate]

i forgot about that one

@last girder ok it is now right?

[last girder]

looks right

and you may want to add arrows on the 2 ends of the curve

because it does go on infinitely

[knotty agate]

oh right

k

all right

now i have to find the domain

(-infinity, infinity) right @last girder?

[last girder]

yes or you can just say $\mathbb{R}$

[hollow light]

cute rizzly bear (nom nom nom)

[knotty agate]

all right

thanks!

[lethal olive]

@knotty agate has given 1 rep to @last girder

[knotty agate]

+close