#For what values of h and k is the following system consistent?
1 messages · Page 1 of 1 (latest)
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with:
+close
- Feel free to nominate the person for helper of the week in #helper-nominations
- Do not ping the mods, unless someone is breaking the rules.
- If you're happy with the help you got here, and the server overall, you can contribute financially as well:
we can solve it without using determinents and all
simply multiply 1st equation by -3
you will notice they are parallel lines
unless they represent same line they are inconsistent
so -3h=k
thats the solution
i hope i am right
consider -3h = k
It's up to you, you can just divide the upper over the lower one and you'll have to solve x, after which you just fill the x and you'll get h, and after which you'll get k because it's a divisor
no idea what this is
check your calculation
which part is wrong?
-3h - k sorry,
this problem is so confusing
just write the second equation as -6x1 + 3x2 = -3h
then divide the first over the second
and it'll get rid of h
and you'll have x to work with
ok ill try that
sorry I'm working this all in my mind
excuse me, try substraction instead of division
division will only nullify the equation
alright will try now
when two equations are the same or are only different by a multiplicative proportion, it will always end up by a self evident conclusion 0=0 or 1=1 etc..
my bad
so would it be -8x1 + 4x2 = k - h
from what ive learnt im only allowed to do these operations
i dont think im allowed to just sbtract them
okay
no worries im super loss, so your help is appreciated
i'll leave this to someone else, I'll try first solving it on paper instead of speculating
ok
for what seems is that the system is always consistent if k = -3xh
the second line of the system is just useless
it's a repetition of the first
So you can just write the solution as the set S = {...(1,-3),(2,-6),(3,-9)...\} of course you won't write it like this I'm just giving you an idea
unless you can give me more context
@latent grove
you will write the set S in terms of h and k belonging to R
or x and y as solution tuples if you don't want to repeat h and k