Limit at Positive Infinity of a Rational Function with embedded squareroot | Mathematics | Page 1

wild hemlock Aug 26, 2023, 8:20 AM

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Screenshot_2023-08-26-14-56-16-897-edit_com.android.chrome.jpg

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Need help with this

ancient sigil Aug 26, 2023, 8:20 AM

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is that for school

wild hemlock Aug 26, 2023, 8:21 AM

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ancient sigil is that for school

Just a review

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Confused with how to factor that radical

ancient sigil Aug 26, 2023, 8:21 AM

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sqrt(16x^8 - x) ~~ sqrt(16x^8) = 4x^4

wild hemlock Aug 26, 2023, 8:23 AM

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Thanks

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So what's like the limit?

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Is it infinity or something?

ancient sigil Aug 26, 2023, 8:24 AM

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substitute what i said in there

ancient sigil Aug 26, 2023, 8:26 AM

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ancient sigil sqrt(16x^8 - x) ~~ sqrt(16x^8) = 4x^4

this will not always work and you have to be somewhat careful about approximations like this but in this case you could see that the denominator is infinity so if the numerator isnt infinity the limit is 0

wild hemlock Aug 26, 2023, 8:27 AM

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Ohh okay thanks

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I've substituted it but somehow I can't get the answer

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The equal sign doesn't make sense

ancient sigil Aug 26, 2023, 8:35 AM

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sqrt(16x^8) = sqrt(4*4*x^4*x^4) = 4x^4

wild hemlock Aug 26, 2023, 8:38 AM

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Wait lemme write it properly

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wild hemlock Aug 26, 2023, 8:44 AM

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ancient sigil sqrt(16x^8) = sqrt(4*4\*x^4\*x^4) = 4x^4

Still doesn't make sense

ancient sigil Aug 26, 2023, 8:45 AM

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maybe you should review properties of exponents and square roots

wild hemlock Aug 26, 2023, 8:48 AM

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Thanks for the response

#Limit at Positive Infinity of a Rational Function with embedded squareroot