continuous function from Rm to Rn

[remote oxide]

can anyone explain to me the last equality ?

[queen sorrel]

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[clear birch]

L is a linear function, so $\forall x \in \mathbb{R}^m, \exists C \in \mathbb{M}_{n,m}$ such that $L(x) = Cx$ and $\norm{L(x)} = \norm{Cx}$.

[solid fog]

Yojda

[remote oxide]

i mean, why is delta equal to epsilon over norm of C ?

[clear birch]

We force $\delta$ to be $= \frac{\epsilon}{\norm{C}}$

[solid fog]

Yojda

[remote oxide]

ok thanks

+close