#Indefinite Integral
10 messages · Page 1 of 1 (latest)
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$\int \frac{4x^5+3}{2x^2} \dd{x} =\int \left(2x^3+\frac{3}{2} x^{-2} \right) \dd{x}=\frac{1}{2}x^4+\frac{3}{2x}+C$
Civil Service Pigeon
Sorry if the reply is late but there are a few things I’m confused about
How do you get from 3/2 x^-2 to 3/2x
Because factorising x^-2 would be -x^-1 no?
Oh that was a typo
+close