#I do not understand physics. Why is this wrong?
solemn whale
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visual shale
i dont understand your doubt
visual shale
which one
solemn whale
what i did is d = at^ 2\
visual shale
the one written in the pic
visual shale
how is v equal to at
solemn whale
velocity is equal to acceleration times time
visual shale
v = u + at right
solemn whale
v = u + at right
no yeah
visual shale
u being initial velocity
visual shale
uh
solemn whale
the correct formula is actually ut + 0.5 * at^2
solemn whale
exactly
royal sonnet
It's because distance, velocity, and acceleration are all functions of time. Velocity is the derivative of distance, and acceleration is the derivative of velocity.
solemn whale
It's because distance, velocity, and acceleration are all functions of time. Vel...
so i cant substitute like that
what i did is wrong
?
royal sonnet
Yeah.
It's actually d = (1/2) at^2 + v_0t + d_0, where v_0 is the velocity at t = 0 and d_0 is the distance at t = 0.
Assuming acceleration is constant.
visual shale
what does underscore represent
royal sonnet
Subscript.
visual shale
oh
solemn whale
It's because distance, velocity, and acceleration are all functions of time. Vel...
wait then how do you combine derivates
to get at^2 * 1/2
(I'm ignoring the rest cuz lets say we start from rest)
royal sonnet
What do you mean "combine derivatives"?
solemn whale
What do you mean "combine derivatives"?
like why is the subtition incorrect
like what is the proper way to reach
that expression
where v_0 = 0
and d_0 = 0
royal sonnet
...if acceleration is the function a(t), you integrate a(t) twice.
solemn whale
k
kindred axle
@solemn whale to help explain things better and since I know there is a difference at least in the US.
Are you in algebra base physics or calculus base physics class?
solemn whale
<@690740719069036606> to help explain things better and since I know there is a ...
calculus (I'm new to it tho)
kindred axle
Ok then distance function
Velocity is the first order derived of distance function
And acceleration is 2nd order derived of the distance function. And then remember everything else techie said. If you have questions just ask
solemn whale
Ok then distance function
Velocity is the first order derived of distance func...
can you show me the derivation? xd
if you want ofc
supple depotBOT
apex predator
lost jay
@solemn whale s=d in this case
@solemn whale another way is with just at² you're assuming all of that acceleration is applied at the instant you start timing, however that is inaccurate. You will constantly accelerate over the time, which means your velocity will have a triangular shape under the graph. and if you recall the area of a triangle it is ½×base×height
your height is velocity which is at and your base is time which is t, so your distance travelled is ½×at×t or ½at²
kindred axle
thanks apex I was eating and my latex is rusty since been out of school for a few years
lost jay
np
solemn whale
that makes sense