#Moment of inertia
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Coffeycharas Chichundarcharan
helpt meh.
...with? You haven't actually said what you're supposed to find.
"Moment of inertia"
as the picture describes
"A cylinder spinning with any line joining 2 points on its 2 faces' circumference as axis." i forgot to mention it was homogenous sorry about that
...look, this'll probably go a lot smoother if I can just see the question as originally written.
Wouldn't it partially depend on, like, the location and angle of the axis of rotation?
We have a cylinder of height "h" and base radius "r". We draw a line passing through the center of mass of this very cylinder such that the line touches the circumference of the faces of the cylinder above and below. What's the moment of inertia of this cylinder along this axis?
yes that's the main factor differentiating this from the rest of the MOIs
Okay, see, before you said any line joining any two points on the circumferences.
Yes, that was my fault
Looking at the Wikipedia page for moment of inertia, this seems like maybe something you could solve with an integral? Maybe a double integral.
Lol
yes.
So what is your problem
I think I'll need some help with what double integral we talking about
This is what I have to put up with when coffee presents a new riddle to me
it tilted
Lmao
I smell like whiteboard marker ink all over
It's also what I have to put up with whenever anyone tries to paraphrase the problem they're working on instead of just taking a picture of it. It's very frustrating.
And very common. Frustratingly common.
Sir it's called a "schizo-rant" by our terminology
...feels ableist.
can you give me some insight on how to form the integrals
i thought of integrating along the Axis of rotation (I = / dI)
but it's kinda weird how it's all set up
Wikipedia says the moment of inertia for a point mass is the mass times the square of the distance to the axis, and the moment of inertia for a rigid body is just the sum of the moments of inertia of the point masses.
Better: Just "rant"
yes that's the definition.
absta hepl.
Yea I can Hepl
technically speaking
How hepl
wait lemme draw it for you
,w hepl
You can just follow this construction btw
Integrate over the volume
see this would be easier by a ton, I'd call it trivial
but
the bottom bits
i don't know how to work with those
...it's a cylinder. So it's symmetrical. And the axis of rotation passes through the center. So... could the MoI just be 0?
No
Its kind of mass but for rotation
but that's the physics part
we can get the I for the whole body by integrating over elemental parts perpendicular to the axis of rotation
...right, sorry. I got distracted by thinking about integration, and in particular how a negative value of a function subtracts from integration.
the bounds are generally of the form a and -a here too
So I thought an MoI of a point mass on the left of the axis would be canceled out by an identical MoI on the right.
Just integrate
You need to use your hand
This is not a problem you can hand-waive easily
$\int r^2 dm$
pratham
how does that help
Lol
@jolly pasture
You just compute it
thats the formula
You know how to represent the 3-form dm
wait i missed a term ig
3 form what
Differentual form of order 3
nope
its ryt
it has been a while so ..
ok
need to divide the figure into small parts
You may also use a density form @glass sphinx the result will not differ
o0 that's doable
I'll let you know if i manage to do it
+close
