#How do you do C?
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im very confused
A) Original area was x^2
New area is x(x+b)=(x^2+3x)
So x^2+xb=x^2+3x so new width is x+3
B) l=x+1, b=x-1
New perimeter is 2(x+1)+2(x-1)=4x so no change in perimeter
But
New area is (x+1)(x-1)=x^2-1
Which is less than og
thsi is answer to A and B as provided by boris
In case c we have perimeter is 4x+8
And length l=x+7
So say width w=x-c
Perimeter is 2(x+7)+2(x-c)=4x+14-2c compare this to the given perimeter and you get 14-2c=8 so c=3
So new width is x-3
i) So change made to width is -3
ii) new area is (x-3)(x+7)
iii) If x equals three that width goes to zero so the pen is no longer a rectangle it's just a line and the cute pigs have nowhere to live 
where did oyu get width = X-c, what is X and C? also how did oyu get the perimetre?
x is the original length of the pen
c is a variable to solve for
perimeter is l + w + l + w = 2l + 2w
Oh ok, but how did you get the perimetre = 4x+8?
because in b, the perimeter is 4x
and in c it says the perimeter needs to increase by 8
Did you get it @blissful wadi
OHHH
yeah I get it
can you guys help me with 2E as well?
X can't be -25 ofc so 5
can u pls, like explain it to me?
cause im kinda confused on that
note that we can express the area of the moat by ...?
the big square - 400 (small square)
now write an equation using x thats equal to 500
ok yes
can you just expand this out, and explain your every step? and where you got each number from? where did you get 2(20x+x*(20+2x))?
so whats the side length of the big square
well a simpler way to think about this is
area of big square - area of small square = area of the shaded
side length of big square is 20+2x
can probably see why
small square has area 400
so
,w (20+2x)^2-400=500
so boris divided it into 4 rectangles
note that there are 2 of each type
the smaller one has area 20x
the larger, x(20+2x)
i still like mine more
Yup that's what I did
But redcliff follow what Samoyed dude just said you'll find that easier
ohhhh ok