#Do I just add the two?
49 messages · Page 1 of 1 (latest)
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No, you need to recall the formulas for sine and cosine of sum.
wdym
change tag to alg
why?
because it's not calculus
this question is from a pre-calc practice test
Still, this isn't calculus.
it can be considered precalc but definitely not calc
Well, I was hoping you would just take a look in your textbook, but alright...
sin(α + β) = sin(α)cos(β) + cos(α)sin(β)
cos(α + β) = cos(α)cos(β) - sin(α)sin(β)
what about tan
Well, as usual, tan(x) = sin(x)/cos(x).
But if you want the formula just for it:
tan(α + β) = (tan(α) + tan(β))/(1 - tan(α)tan(β))
ok one sec lemme do and show u
i did the sine one but i got some decimal
0.6914
That's wrong. And don't round.
oh
Do we just do like this
What? No.
We have cos(α) = √(5)/5, not cos(√(5)/5). You need to find α and β first.
oh
After that, you will also need to use the following identities:
sin(arcsin(x)) = cos(arccos(x)) = x
sin(arccos(x)) = cos(arcsin(x)) = √(1 - x^2)
is a still a decimal
Don't round, as I said. What did you get?
1.10714871
i did before it didnt work
so i tried this way
and it still didnt work
Fine...
First of all, what did you get as the solution of cos(α) = √(5)/5, considering α is in the first quadrant?
im am confused
What do you mean?
like the decimal one?
No!
bruh im stupid
Did the many times I told you not to round not say anything?
Why would you even round?
im so lost
If that's the case, return to your textbook and practice solving elementary trigonometric equations first.
why are you solving cos(α) = √(5)/5 💀
Hm. Well, true, we can get sin(α) without solving it.