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[oak umbra]

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[acoustic ridge]

you can take both side to some power to make both exponents integers
that may help you

[river thorn]

impossible

[acoustic ridge]

avoid helping if you aren't comfortable with the problem type 😅

[river thorn]

thanks for reassuring me

[river thorn]

Idk I tried can u show me how to do it plz

[acoustic ridge]

so we will basically multiply by the lcm of the denominators

which is 6

so we get y^15 = x^8

note that 15 and 8 share no factors

now y has some prime factors p^a*q^b...

where p and q are primes

[river thorn]

What I lcm

[acoustic ridge]

least common multiple

[acoustic ridge]

or i guess we can call it 2^a*3^b*5^c...

and due to exponent rules, taking y to the 15th power makes all the exponents multiplied by 15

so we end up with a number where those exponents are all divisible by 15

the same logic holds on the right side
those exponents are all divisible by 8