Somebody Check my work? <3

[deep flower]

Hey! So I'm not confused by this topic, but I'm wondering if somebody could check my work here because I'm pretty sure I got the right answer...

[stray plover]

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[dense mortar]

there's no work to check

but you're just using a formula tbh

[deep flower]

yeah like

@dense mortar is it NOT just an integral PI [0, 27] (2sqrt(x))^2 ??

[dense mortar]

nope

it's a surface area

[deep flower]

but disk method just works??.. why does it

oommml

okay nvm ik the formula god I can't read im sorry

[dense mortar]

"...revolving the graph..."

[deep flower]

wait rq is surface area revolutiion pi or 2pi

it's like f(x)sqrt(1-f'(x))

but I forgot if it's 2pi or pi at the front, p ure its 2 pi

[dense mortar]