#double integral

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rotund shadow
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Hm.
As far as I understand, we have a parabolic plate and we need to find the equation of its parabolic side given the coordinates of its center of mass, right?
Suppose the parabola is y = ax^2 + bx + c.
We see that it passes through (0, 0). So:
y(0) = c = 0
So, we are left with y = ax^2 + bx.
Now, to find a and b we need to consider the center of mass. So, apply the formulas for them with f(x) = ax^2 + bx. Looking at the picture, we get the limits:
0 < y < ax^2 + bx
0 < x < 1
Can you calculate the integrals?

sleek lake
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thank you for taking your time to give me an answer, I will now be able to calculate the integrals

rotund shadow
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Great! You're welcome 😁

sleek lake
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and by calculating xg I find this

rotund shadow
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I already said that the limis are 0 < y < ax^2 + bx, 0 < x < 1.

sleek lake
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leaving a and b unknown ?

rotund shadow
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Yeah. We will be able to find them after we find both integrals.

sleek lake
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so double integral with one of them has 0 and 1 for limits (x) and the other 0 and ax^2+bx (y)

rotund shadow
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Yes.

sleek lake
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So m could be that ?

rotund shadow
sleek lake
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Xg and Yg or Mx and My ?

rotund shadow
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The static moments, M(x) and M(y).

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So, what did you get?

sleek lake
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I'm still searching

rotund shadow
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Alright.

sleek lake
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I understand it's a small surface element multiplied by lever arm

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and with µx/m we will have Xg

rotund shadow
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Yeah, we will have M(x)/M = X(g) and M(y)/M = X(y). That will be the system of equations.

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So, did you calculate M(x)?

sleek lake
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I have this but it is not a system

rotund shadow
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No, wait. That's not what you need to do.

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First, calculate M(x) and M(y).

sleek lake
rotund shadow
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Well, for M you integrated just dxdy.
For M(x) you do the same, but integrate xdxdy. And for M(y) you integrate ydxdy.

sleek lake
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Like that ?

rotund shadow
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Can't see it very well. It should be (6a^2 + 15ab + 10b^2)/60.

sleek lake
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I have a mistake (6a+15ab+10b^2)/60 , you have in parentheses 6a^2 and me 6a

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And M(y) it could be that

rotund shadow
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No, that's incorrect.

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You mixed up the limits. The inner integral is xdy. If you want, you can factor out x from it.

sleek lake
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but if I keep the same limits I will find the same thing as for M(x) right?

rotund shadow
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No.

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Fine, let me show.

sleek lake
rotund shadow
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This is what we get.

sleek lake
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Ohhh okay ! So I had to reverse to calculate Mx in my double integral and then after all these steps you have to solve the system to have a and b, right?

rotund shadow
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Yes.

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To solve the system, I recommend expressing a or b from the first equation and substituting into the second. That will give you a quadratic equation.

sleek lake
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the only way to check is to take for example the first equation and replace b with the number and see if we had the same a, right ?

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because a = -1 and b = 2

rotund shadow
sleek lake
umbral glacierBOT
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@sleek lake has given 1 rep to @rotund shadow

rotund shadow
sleek lake
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+close