Hm.
As far as I understand, we have a parabolic plate and we need to find the equation of its parabolic side given the coordinates of its center of mass, right?
Suppose the parabola is y = ax^2 + bx + c.
We see that it passes through (0, 0). So:
y(0) = c = 0
So, we are left with y = ax^2 + bx.
Now, to find a and b we need to consider the center of mass. So, apply the formulas for them with f(x) = ax^2 + bx. Looking at the picture, we get the limits:
0 < y < ax^2 + bx
0 < x < 1
Can you calculate the integrals?
#double integral
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thank you for taking your time to give me an answer, I will now be able to calculate the integrals
Great! You're welcome 😁
I think I have an error 😅, when I calculate m I have this
and by calculating xg I find this
Wait, wait. Why did you take those limits?
I already said that the limis are 0 < y < ax^2 + bx, 0 < x < 1.
leaving a and b unknown ?
Yeah. We will be able to find them after we find both integrals.
so double integral with one of them has 0 and 1 for limits (x) and the other 0 and ax^2+bx (y)
Yes.
So m could be that ?
Yes. That is the mass of the plate.
Now, you need to find the moments.
Xg and Yg or Mx and My ?
I'm still searching
Alright.
I understand it's a small surface element multiplied by lever arm
and with µx/m we will have Xg
Yeah, we will have M(x)/M = X(g) and M(y)/M = X(y). That will be the system of equations.
So, did you calculate M(x)?
I really don't know how to calculate these static moments with the data I have
Well, for M you integrated just dxdy.
For M(x) you do the same, but integrate xdxdy. And for M(y) you integrate ydxdy.
Like that ?
Can't see it very well. It should be (6a^2 + 15ab + 10b^2)/60.
I have a mistake (6a+15ab+10b^2)/60 , you have in parentheses 6a^2 and me 6a
And M(y) it could be that
No, that's incorrect.
You mixed up the limits. The inner integral is xdy. If you want, you can factor out x from it.
but if I keep the same limits I will find the same thing as for M(x) right?
okay
This is what we get.
Ohhh okay ! So I had to reverse to calculate Mx in my double integral and then after all these steps you have to solve the system to have a and b, right?
Yes.
To solve the system, I recommend expressing a or b from the first equation and substituting into the second. That will give you a quadratic equation.
oh okay
the only way to check is to take for example the first equation and replace b with the number and see if we had the same a, right ?
because a = -1 and b = 2
Yes, very good!
So, our parabola is y = -x^2 + 2x.
YES Thank you very much for your explanations and your time !!
@sleek lake has given 1 rep to @rotund shadow
You're welcome!
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