#could some one help explain this math problem
4 messages · Page 1 of 1 (latest)
Oh
Thanks for helping I now get how it works
yw
4 messages · Page 1 of 1 (latest)
call f^-1(x), F(x)
by definition F(f(x)) = x
then F'(f(x))f'(x) = 1
Oh
Thanks for helping I now get how it works
yw