#please help im unable to evaluate this integral
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diviirockgod6
i identified the integral as Beta(-3/2, 11/2)
but i am not getting any sqrt(2) in my answer..
Well, you have x^(9/4)/(1 + x)^4. So, n - 1 = 9/4 and m + n = 4.
Ah, you want to evaluate it, too.
oh wait
9/4
i wrote 9/2 ๐
mb
wait lemme try again
beta(3/4, 13/4)
yeah please help i dont know
how to evaluate this
Well, let's see.
ฮ(3/4, 13/4) = ฮ(3/4)ฮ(13/4)/ฮ(4)
ฮ(4) is 6.
For the numerator we do the following:
ฮ(3/4)ฮ(13/4) = (9/4)ฮ(3/4)ฮ(9/4) = (9/4)(5/4)ฮ(3/4)ฮ(5/4) = (9/4)(5/4)(1/4)ฮ(3/4)ฮ(1/4)
Then we recall that ฮ(x)ฮ(1 - x) = ฯ/sin(ฯx) for 0 < x < 1, so:
ฮ(3/4)ฮ(13/4) = (9/4)(5/4)(1/4)ฯ/sin(ฯ/4) = 45ฯโ(2)/64
So:
ฮ(3/4, 13/4) = (45ฯโ(2)/64)/6 = 15ฯโ(2)/128