#Stuck on vector cross product
unkempt tangleBOT
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acoustic thunder
The line of shortest distance will be perpendicular to given line
You can use the direct formula too @cobalt sandal
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This is hard to read
cobalt sandal
ahh sorry
acoustic thunder
What I was saying to do is getting the direction ratios of perpendicular line,\
$$(3+2t , -7+4t , -2-3t)$$
Then take it's dot product with direction ratios of line to get the point of intersection\
$2(3+2t)+4(-7+4t)-3(-2-3t) =0 \Rightarrow -16+29t=0 \Rightarrow t=16/29$\
Now the two points we get are $(1,2,3)$ and $(4+2(16/29) , -5+4(16/29) , 1-3(16/29))$, then get the distance between them
river juniperBOT
fäf kaka
acoustic thunder
This will be equal to
acoustic thunder
,w sqrt((29(4)+2(16)-29)² + (-7(29)+4(16))²+(-2(29)-3(16))²)/sqrt(29)
river juniperBOT
acoustic thunder
,w sqrt(29²+5²+26²)/sqrt(29)
river juniperBOT
acoustic thunder
Your handwriting is hard to understand
cobalt sandal
wait
my answer without 29 on the bottom is right
I thought you needed the magnitude of that vector
acoustic thunder
I don't understand your approach
cobalt sandal
I did the cross product to find the normal vector
and then using properties
I rearranged it to find the distance
acoustic thunder
Wait cross product of what?
acoustic thunder
What is Po and P
acoustic thunder
I did not label well
Yeah hard to understanding
acoustic thunder
And what is a?
cobalt sandal
the vector of the line
acoustic thunder
is the normal right
Yeah seems right
cobalt sandal
thank you seems right
cobalt sandal
I plugged in t=0
acoustic thunder
Your work seems too much
acoustic thunder
I plugged in t=0
No that'd wrong then
You will get the right normal but Po is not the point the distance line passes through
cobalt sandal
answer is root 1542/29