why would the direction downward ever be mgsintheta with sohcahtoa
#How do I work this out, it doesn't make any sense to me
young widget
glossy turtleBOT
why would the direction downward ever be mgsintheta with sohcahtoa
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young widget
the force downwards is the hypoteneuse which is calculated with opposite/sin(theta)
so why is it multiplied??
fossil lake
it's not just gravity and friction on the block, it's also the normal force
fossil lake
i'm not sure
the friction is not mg sin(theta) though
as theta increases the friction has to increase to infinity
oh no it doesnt nvm
it just increase from 0 to mg
young widget
mgsin(theta) is the force acting down the ramp
the mark scheme as useful as always just says "(F = ) 19gsin23° to give 72.8 (N)"
warm nova
@fossil lake
fossil lake
yes but how does that help me
marsh hornet
the mark scheme as useful as always just says "(F = ) 19gsin23° to give 72.8 (N)...
mass is 19 kilos, you want weight (19g) and then you want to adjust for the slope
hence 19gsin23
young widget
mass is 19 kilos, you want weight (19g) and then you want to adjust for the slop...
this doesn't explain why they're multiplying it like that though
fossil lake
.
marsh hornet
wdym
19gsin23 because the force dragging it down the slope would be 0 if there was no slope
young widget
Alright I got it
this man, he is a god
he explains it incredibly well
who is this alp guy
warm nova
Me
marsh hornet
tl maths is good allegedly, i knew some people who depended on him when i was doing fm