#radius
53 messages · Page 1 of 1 (latest)
Just remember that the water will cover same volume in cone as its in hemisphere
So calculate volume that water is taking in hemisphere which is two fifth volume of hemisphere
Then that will be equal to volume of water taking in cone. Take height h=12
Put both equal and solve for variable r
hi guys i still not sure how to do it
Think about this as this take some water in a bowl then transfer it to a glass. The quantity of water will be same no?.Just that water is liquid so it get itself adjusted with the shape you put it in.
Thats the concept here. And its taking same space(volume) in bowl or in glass.
Now read this again try it
so i do volume of shepre divide by 2/5
No hemisphere which is half of sphere
Half of volume of sphere multiply by two fifth = volume of cone with h = 12
Yeah divide by 2 or multiply by 1/2 same thing
It would give you formula of hemisphere 2/3 pie r^3
then what do i do
Is it 2 3 pi r 3
452.38
In terms of pi
144
28.8
That is 1/5
57.6
Ok the depth of the water in the cone is the height of it
We need to find radius and we know area and height
We have 1/3 pi r^2 * h = A
1/3 * pi r ^2 * 12 = 57.6 pi
Solve for r
So area is 57.6pi and height is 12cm so do I times them together
No
This
Divide pi from both sides to get rid of it
Then solve for
r
Is this what I do to find the radius