I need help with this

[azure crypt]

Determine the Cartesian equation of a line in 3D that is perpendicular to the plane CZ and goes through the point A (1,2,3)

[floral fox]

1. Wait patiently for a helper to come along.
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[turbid copper]

not given plane CZ, but if you want the line perp. to a plane, the direction vector has to be perp. to the plane, hence is the normal vector of the plane

[azure crypt]

Oh to solve it you need more details for CZ?

So the question I was given in homework was not proper?

[turbid copper]

You're saying that as if I know the question verbatim

Based off what you typed it is incomplete, since there is nothing about plane CZ, other than it's called CZ

no equation nor details.

[turbid copper]

and the plane XZ is first mentioned in that question?

or, perhaps, it is mentioned somewhere else you are omitting

or does it mean the xz plane?

[azure crypt]

I meant xz plane sorry

[turbid copper]

then you have enough info since you know what the xz plane is

[azure crypt]

And I never was questioning if you knew it or not. I was just saying that since my teacher makes the homework questions he sometimes makes mistakes.

I apologize if it came of in a bad way. I appreciate your help.

Another question I have

What is the difference between the scalar equation and Cartesian equation.

Scalar is ax + by +cz =0

Cartesian is ax+by + cz + d = 0

Is this the difference?

[turbid copper]

those are the same thing, the 1st one is just d=0..