hii quick question, how were these solved? what are the formulas used to get to this
#math
steel vortex
green horizon
There are three formulas you need for these:
A = (1/2)ab*sin(theta)
a/sinA = b/sinB = c/sinC
c^2 = a^2 + b^2 + 2abcosC
So for example in 11) You'd use the sine rule (second one) to find the length ST, then use the first area formula
green horizon
There are three formulas you need for these:
A = (1/2)ab*sin(theta)
a/sinA = b/s...
where the triangle is labelled like this
astral granite
There are three formulas you need for these:
A = (1/2)ab*sin(theta)
a/sinA = b/s...
Heron's formula for 14, too.
green horizon
Heron's formula for 14, too.
True, I'd been taught to use the law of cosines to find an angle then chuck it into the area formula, but I prefer your way