#someone **check** please
25 messages · Page 1 of 1 (latest)
Several comments.
- Don't forget about units.
- in 1, v(y) is actually exactly 1100 ft/s.
- In 2, you also need to find the magnitude of the velocity. Also, if you meant this angle as the standard way of counting them (counterclockwise from the positive x-direction), then it's wrong. If you count it from north (as you did), you need to specify the direction in which you are rotating.
- Vx ≈ 1905, Vy ≈ 1100 ft/s
- The ship's actual velocity is approximately 11.7 mph, and it is traveling in a direction approximately 30.96 degrees north of west.
do u mean it like this?
im confused
- Units should be everywhere where they are needed. So, v(x) ≈ 1905 ft/s, v(y) = 1100 ft/s.
- Speed (not velocity - velocity is a vector, while speed is its magnitude) is correct. But the angle is west of north, not north of west. Also, you rounded it incorrectly.
The ship's actual speed is approximately 11.7 mph, and it is traveling in a direction approximately 30.96 degrees west of north.
wait whats the right one
they said 30.96 is right
30.9637565166 degree
Well, it asked you to round to nearest tenths. So, 31.0 degrees.
Ohh!
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Perform the vector operation 2(4r-2s)-5(3r-s), given r = < -4, 3 > and s = < 2, -5 >. ( Input your answer in this format <2,3> )
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Find the position vector of z if l z l = 3 and the direction angle of z is 195 degrees. (Round your answer to the nearest hundredths)
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Find the unit vector in the direction of vector s = < 40, -9 >
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A bullet is fired from ground level at a speed of 2200 feet per second at an angle of 30 degrees from the horizontal. Find the magnitude (speed) of both the horizontal and vertical components of the velocity vector. (Round your answers to the nearest whole number)
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A ship’s captain sets a course due north at 10 mph. The water is moving at 6 mph due west. What is the actual velocity of the ship, and in what direction is it traveling? (Round your answers to the nearest tenths)
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< 30, -26 >
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< 0.9848, -2. 8925 >
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<0.9756, -0.2195>
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v(x) ≈ 1905 ft/s, v(y) ≈ 1100 ft/s.
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The ship's actual speed is approximately 11.7 mph. While it's traveling in a direction of 30.96° or 31.0° west of north.
is it okay if you could check one last time
Hold on, I'm checking.
thank uu
Well, again, can you show?
😭
its embarrassing 😍