#help (trigonometry )
23 messages · Page 1 of 1 (latest)
What about the rhs ?
The idea is that you're supposed to manipulate one of the sides to end up with the result on the other side
In this case, it's more intuitive (at least for me) to manipulate the LHS
Since we're normally better at making messy things simpler than making simple things messy
But once you apply sum of cubes, you'll see how stuff reduces
Especially once you use the ||Pythagorean identity||
Lhs will be equaled to this
So don’t we need to do the mhs and rhs to prove to be this identity
?
Can you send all your working so far?
It’s pretty rough I will do it again
👍
Note that $\sin \theta \cos \theta=\frac{1}{2}\sin 2\theta \implies \sin^2 \theta \cos^2 \theta =\frac{1}{4} \sin^2 2\theta$
Civil Service Pigeon
Ah i see
Can you take it from here?