#matrix
163 messages · Page 1 of 1 (latest)
First, simplify the matrix on the RHS by factoring 5 inside of it.
Then, subtract that matrix from both parts.
Finally, multiply both parts by -(1/2). That will allow you to express X.
can you solve the whole question for me
its a very important homework for me
and i couldn't solve due to my unawareness
🙏
Um, no. Try it yourself first.
i dont know what does RHS mean... i tried but i couldn't solve it.
can you please help me about finding the answer
its really important...
right hand side
it means the right hand side
reading comprehension has nothing to do with math
"the matrix on the right hand side"
if you know what a matrix is
and know what "right" and "side" mean from your elementary days, you can put two and two together to understand what it means
but anyway, how would you solve something like 7=-2x+3?
can you teach me
no
sure
It's literally the same as with a simple linear equation, though.
looking at it entrywise, you're just solving 6 equations akin to 7=-2x+3
you are just bullying me with your knowledge man, there is no shame in not knowing the shame lies in not finding out
and i just wanted to learn sth
then attend class
thank you anyway
Sorry, but you don't seem to even be trying to do anything. You just want us to solve it for you.
You've demonstrated you know the process, you just need to sit there and do it
we did
I already did.
you're doing the exact same thing
but with matrices, instead of numbers
the exact same idea of addition and scaling hold, and are done in the "no shit sherlock" manner
First, simplify the matrix on the RHS by factoring 5 inside of it.
how can i do this step
tell me
$c[A_{ij}]=[cA_{ij}]$ entrywise
omegabet_
lets be solution oriented
for any scalar $c$ and matrix $A:=[A_{ij}]$
omegabet_
that's how you multiply a matrix by a scalar
you just multiply each entry of A.. by the scalar
Why are so many people so incredibly strongly opposed to solving things generally? I can't understand it...
Likewise, as you will recall from your notes/lecture/class whatever, $[A_{ij}]+[B_{ij}]=[A_{ij}+B_{ij}]$, provided $A$ and $B$ are of the same size
omegabet_
The individual task is not what's important. The general principles and algorithms is what's important.
guys i tried to solve this equation
11/10 -15/2 -23/4
-41/10 7/2 45/4
is that correct answer
what do you think
i done all of the steps
@lunar quail @fair pagoda
post your steps
No. Can you show what you've done?
matrix x = a,b,c,d,e,f
1 = (-2a + 5)(-5) + (-2b + 5)(-3) + (-2c + 5)(-4)
7 = (-2a + 5)(-5) + (-2b + 5)(-1) + (-2c + 5)(-4)
-6 = (-2d + 5)(-5) + (-2e + 5)(-3) + (-2f + 5)(-4)
9 = (-2d + 5)(-5) + (-2e + 5)(-1) + (-2f + 5)(-4)
then i simplified this
into this
1 = 10a - 25 + 6b - 15 + 8c - 20
7 = 10a - 25 + 2b - 5 + 8c - 20
-6 = 10d - 25 + 6e - 15 + 8f - 20
9 = 10d - 25 + 2e - 5 + 8f - 20
more simplifiements
10a + 6b + 8c = 61
10a + 2b + 8c = 57
10d + 6e + 8f = -16
10d + 2e + 8f = -26
that looks like complete nonsense
why
cause it's wrong
its my own method
by your notation, you have $1=-2a+5(-5), 7=-2b+5(-5)$, etc
omegabet_
since, again, + and scaling is done component wise
guys i need to find c1 and c2
can you help me
btw the other question is solved by me
i found my mistake
and i fixed it
Note that by Cayley-Hamilton a matrix must satisfy its own characteristic polynomial. So, find it.
To remind you, you can find it as det(M - λI), which will be a polynomial in λ.
I feel like if they're just learning matrix algebra, they wont know Cayley Hamilton
i know the hamiltons theorem bro
I somehow doubt that but ok
then just apply CH as was said
i heard about the theorem but im not into it
then you dont know "the hamiltons theorem"
i know
then apply it..
i just dont have detailed information about it
what does CH say then?
do you know the human anatomy omegabet
that's relevant how?
what does the Cayley Hamilton theorem say?
Uh, Bugra, if you say you know a theorem, be prepared to formulate it. Otherwise it just seems that you are lying.
okay
let me tell you
but promise me
then you will answer my question omegabey
t*
When you tell me how my knowledge of lungs is at all relevant to matrix algebra, and after you have answered my question, then sure I'll humor you
hamilton says that a characteristic polynomial expression of a real square matrix should be equal to zero matrix
so apply it
also it can be complex square matrix
then
do you know our lungs
yes you know our lungs
yes, I know what lungs are
okay
how does it work
can you explain me
no
you cant
so you dont know lungs
that what you said
thats
So you know the theorem, but you don't what the theorem says?
That right there is a bit of a paradox, math theorems arent like lungs
i told you what the theorem says
It seems that you just want to fool around instead of discussing your question. I won't bother anymore with this.
There are atoms but we can't see them, so there are no atoms?
I do not intend to joke
Well anyway you have the answer to your question, gl
and you're wasting my time and your own 
You've answered your question yourself, just apply CH. gl