cube

[quasi light]

@urban pagoda

[fallen sorrel]

Find the perimeter of the base circle and multiply it by the height of the can

Oh and add 2 times the area of the base circle

Like that you’ll have the whole surface area

[quasi light]

I tryed and I got 36

And the other answers is 113.1

I think am wrong

I tried getting help from my help but he couldn't

[fallen sorrel]

Mmm well to get does the surface area include the bottom ?

[quasi light]

Top and bottom is 8

Right ant left is 15

I don't think I will fish my work bc there like 40 of theses

[warm crypt]

2×16π+(8×15)π

32π+120π

152π

[quasi light]

Oh

[warm crypt]

477.5

gotta add your top and bottom, and your sides which are dhπ

diameter, height, pi

[quasi light]

Oh wait so I put in simplest from

Ok

[fallen sorrel]

Yeah sorry I should’ve given the formula

[quasi light]

Oh nah ots fine

@warm crypt I got it wrong

But I thi k I did the steps wrong

[warm crypt]

radius of 5cm, so you have 25π on top and 25π on bottom, 50π together
then for the body it's 4×2×π×5 so 40π
together that's 90π or approx 282.7, now we want to divide 2500 by this which is 8 and some change, but it asks for completely painted cylinders, so it's just 8

[quasi light]

Wait so u divide 282.7 by 2500

It was 3 thats why I got wrong

[warm crypt]

no, thats a different question

[warm crypt]

no, 2500 by 282.7

[quasi light]

Thats why I got wrong I was confused

Wait so u don't divide

[warm crypt]

you divide 2500 by 282.7

[warm crypt]

yes, then you remove the decimal part as it wants complete paint

leaving 8

[quasi light]

So I remove to 7

[warm crypt]

repeat that method for the new question

[quasi light]

The one next to the eight

[warm crypt]

no, you have 8.84, 0.84 is less than 1 so it's just 8

[quasi light]

But am confused why I do this look

Ik thats not right

[warm crypt]

thats the curved surface area

[quasi light]

Oh thats why

[warm crypt]

you want to add the top and bottom, which is 50 pi total

(30+50)pi

2500/(80pi)

[quasi light]

Wait so is the 5²

That makes it 50

[warm crypt]

9 whole ones

well its 2*5^2

pi

so yeah 50

[quasi light]

Ok

Am not sure if am right

[warm crypt]

2500 on top, not under

2500 divided by 80pi

[quasi light]

Bc this how they doing it

And its mad confusing

[warm crypt]

thats 80pi divided by 2500, not what i said

not what theyre doing either

[quasi light]

Oh

2500 divide by 80pi

[warm crypt]

bracket your 80 and pi together

2500/(80pi)

[quasi light]

How do I do that

[warm crypt]

otherwise it's taking it as 2500pi/80

[quasi light]

On the calcultor

[warm crypt]

with the brackets

to the right of C

[quasi light]

So how its not going other way

[warm crypt]

remove the second x

[warm crypt]

yes, but you want how many completed ones, 0.94 is not completed, so it's just 9

[quasi light]

Ok

[quasi light]

@warm crypt would u help me out with this

Its very hard

[urban pagoda]

Suppose you have the initial loan is X(0) and it increases every year by a fraction p.
Then the loan at year n is X(n) = X(0)(1 + p)^n.
In your case X(0) = 800, p = 0.28, n = 14.

[quasi light]

Idk if its this

[urban pagoda]

Well, you didn't round correctly.

[quasi light]

Oh

Thats why

@urban pagoda i have been doing it but it says am wrong

Can u help me out

[urban pagoda]

Well, the formula is the same.

[quasi light]

I got

7928.9

[urban pagoda]

Again, the rounding is not correct.

[quasi light]

Is the answer

7926.0

[urban pagoda]

No, as I said, this is fine, you just didn't round correctly.

What did you get exactly? Or, at least with some more decimal places.

[quasi light]

Wait so whats the answer bc me and my frind are on same question

And we have spent about 30 mins on it

[urban pagoda]

As I said, your only mistake is rounding. You rounded to 1 decimal place, while the question asks for 2.

[quasi light]

Am so confused bc its says for 1

7928.87

Got it

[urban pagoda]

That's correct.

[urban pagoda]

1p is a hundredth of a pound, hence 2 decimals.

[quasi light]

Ok thanks sir

[urban pagoda]

You're welcome!

[urban pagoda]

Same formula, as before, but you need to express X(0) from it.

[quasi light]

Am stuck

[urban pagoda]

Well, just divide both parts by (1 + p)^n.

[quasi light]

K

So what do I didvide

[urban pagoda]

Well, as we've established above, X(n) = X(0)(1 + p)^n. You know n, X(n) and p and you need to find X(0).

So, express X(0) from the formula by dividing both parts by (1 + p)^n.

[quasi light]

Dont even get it tried all stuff keep getting it wrong

[quasi light]

Its impossible it took me 2 hours but still

[urban pagoda]

Well, um...

It's literally what I said, that's all...