#Logarithm equation not working out when replugging values
edgy tendon
when I replug pi/4 into b)
log4(3sinx) + 1/4 = log2(sqr[3-cos2x]
the equation doesnt work out
instead im getting an inequality
why is that because I checked the answer key afterwards and it also said the answer was pi/4
and mathematically it should work out no?
unless im missing something
slow prairie
instead im getting an inequality
What do you mean, you're "getting an inequality"?
edgy tendon
like they're not equal
Im getting to log4(3sinx) +1/4 < log2(sqr[3-cos2x])
since log4(3sinx) is about -2.3
and log2(sqr[3-cos2x]) is about 0.5
slow prairie
...what?
slow prairie
since log4(3sinx) is about -2.3
That's not true at all. That would imply 3sin(x) > 16, which implies sin(x) > 5.
Wait, negative. I thought that was a tilde.
Representing approximation.
slow prairie
since log4(3sinx) is about -2.3
I mean, log_4(3sin(x)) isn't really anything. You need a value of x for that to equal something.
Like, you need to show me what you're actually doing that is actually getting you these results.
slow prairie
...no, show me the part where it stops working.
edgy tendon
Oh I see whatchu mean
slow prairie
since log4(3sinx) is about -2.3
Show me where these values come from.
slow prairie
...that's not showing me how you got those values.
edgy tendon
I just put it in my calculator
slow prairie
I just put it in my calculator
You put it in your calculator wrong.
What's sin(pi/4)?
slow prairie
Like, how did you even believe that you got a negative value?
slow prairie
Why was your calculator ever in degree mode?
slow prairie
And why wasn't it in degree mode when you did arcsin?
edgy tendon
guess I forgot to switch it
slow prairie
The more answers you give me, the more questions I have.
edgy tendon
oh I just knew arcsin of root 2 over 2 was pi/4
just showing the work
yeah I just realized why would 4^-2.5 give 3*root2/2 +1/4 lol
im trippin
slow prairie
yeah I just realized why would 4^-2.5 give 3*root2/2 +1/4 lol
Alternately, 3/sqrt(2) > 1, therefore a logarithm of it in any base must be positive.
edgy tendon
oh true
wait why are we doing 3/sqr(2)?
u mean 3*sqr(2)/2? or am I just having another moment of being tired
slow prairie
u mean 3*sqr(2)/2? or am I just having another moment of being tired
...sqrt(2)/2 = 1/sqrt(2).
Multiply by sqrt(2)/sqrt(2).
edgy tendon
ok yeah sorry im being dumb