#Cauchys Integral formula

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leaden agate
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How can I use cauchys integral formula here? I only know f(z) / (z-a), but here I have f(z)/(z*(z+1))?
We know that f(0) = 2 and f(-1) = 1

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golden chasmBOT
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  1. Wait patiently for a helper to come along.
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tacit crest
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Split $ \frac{1}{z(z+1)} $ to $\frac{A}{z} $ and $\frac{B}{z+1}$

versed nicheBOT
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Altair

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tacit crest
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A=1 and B=-1

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Then you have that your integral is f(0)-f(-1)