#functions I need help
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substitute in x=p
-2p²+p = 28
2p²-p+28 = 0
solve for p
oh
-2p²+p = -28
2p²-p-28 = 0
solve for p
I'm quite bad at math so how do I exactly... Solve for p?
quadratic equation
find 2 number m and n such that:
m+n = -1
mn = -28×2 = -56
or use the quadratic formula
yes
Yep
what is it
-7/2 , 4
But for g(3) do we use the previous equation?
meaning that we throw away -7/2
Mhmm
and have p = 4
Alright
and then we remember that
g(x) = -2x^2 + p
so we plug in our value of p, that is 4
and we obtain
g(x) = -2x^2 + 4
and now all thats left to do is finding the value of g(3)
yes