#I need help with these questions
21 messages · Page 1 of 1 (latest)
1st one you get $\frac{\cos(t)(\sin(t)-1)+\cos(t)(\sin(t)+1)}{(\cos(t)-1)(\cos(t)+1)}$ which you then expand and simplify
mid.
second one you Binomially expand:
1/cosy = secy
sec²y+2secytany+tan²y
2secytany = 2/cosy × siny/cosy
2siny/cos²y
all have denominators of cos²y now
(1+2siny+sin²y)/cos²y
which is just (1+siny)²/cos²y
to which we rationalise our denominator on the RHS
(1+siny)(1+siny)/(1+siny)(1-siny)
(1+siny)²/(1-sin²y) = (1+siny)²/(cos²y)
first question
second question
um
for this one I think the question is wrong
forgot to mention it
no
the question is correct
sin²t-1≠cos²t
other way around, that's where you dropped the minus
sin²t-1=-cos²t
@chilly niche
oh yes mb
dw