#Prove This Statement (Algebra)

42 messages · Page 1 of 1 (latest)

pseudo vigil
fading jayBOT
#
  1. Wait patiently for a helper to come along.
  2. Once someone helps you, say thank you and close the thread with: ```diff
    +close
weak fractal
#

Do you have any additional information?

#

Like if m = n? @pseudo vigil

glacial stump
#

Doesnt need it

#

Combine the fractions, solve for $a^{m-n}$, and substitute the solution into the original statement to prove equality

last flameBOT
#

Ephesians 2:8-9

glacial stump
#

$\frac{2}{1+a^{m-n}}=1$

last flameBOT
#

Ephesians 2:8-9

glacial stump
#

And so on

weak fractal
#

But you're not really proving anything are you?

grim summit
glacial stump
#

Assuming the statement is true, we can show it leads to a true conclusion

#

We do get that a^(m-n) is 1

#

And then 1/2 + 1/2 = 1

#

That's what I would do with the given information

weak fractal
#

But you're being asked to prove the statement is true

glacial stump
#

Which it is for a specific value of a^(m-n)

weak fractal
#

This question is not worded properly anyway

glacial stump
#

I mean if you have other ideas feel free to write them

#

From what is given, this is all I can do and assume needs to be done

crimson skiff
#

@pseudo vigil prove that god exists

pseudo vigil
pseudo vigil
pseudo vigil
#

i have done a more complex version of it, but somehow i cant do this one

crimson skiff
#

@pseudo vigil the question isn't well defined. Wth is α and what are m, n?.

pseudo vigil
#

idk

#

the question never said anything about it

#

i worked on a similiar but much more complex problem, and i cant seem to do this one

crimson skiff
#

@pseudo vigil bruh...

#

Obviously the equation doesn't hold for any a, n, m.

#

It is not a identity like sin²θ+cos²θ=1 which holds for all θ in R.

pseudo vigil
#

middle school

#

i suddenly blanked

crimson skiff
#

@pseudo vigil Pick α=0, m=2, n=1

#

You will get 2=1 which is incorrect

#

Maybe it is from an exam and all you remember is that expression and not the whole question.

#

So since the equation doesn't hold for any a, n, m . They must have some of other definition than just any three random numbers.