#(square root-9) power of 2
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@frozen scroll is this $\sqrt{-9}^2$ what you mean
Altair
Yes
Wait up the - should be in the left
More left
I don't think this is used. I think the n-th root definition is only for positive integers.
I guess you could say it is ((9)^(-1))^2=(1/9)^2=1/81
If you mean (-sqrt(9))^2 it’s because it turns into (-1•sqrt(9))^2 = -1•sqrt(9)•-1•sqrt(9) or (-1)^2 • sqrt(9)^2 which is 1•9 or 9
Basically
x^2 = (-x)^2
However most people consider -x^2 (without parentheses) to be -(x^2)
As the negative is like multiplying by -1