#Inscribed, circumscriebed circles problem

30 messages · Page 1 of 1 (latest)

drowsy kelp
#

Everyone knows we can easily find these 2 if we are given a triangle, but what about the other way around? Given 2 circles, the inscribed and circumscribed circle, can we find back the original triangle?

lime shuttleBOT
#
  1. Wait patiently for a helper to come along.
  2. Once someone helps you, say thank you and close the thread with: ```diff
    +close
rotund willow
#

currently operating on 1 brain cell, but yeah I'd think so

#

the inscribed circle is has 3 tangents, and will touch each of those so that the angular bisectors all intersect the centre of the circle

#

because the origin of the inscribed circle is the incenter of the triangle

#

and then you get your vertexes from the circumcircle

rotund willow
#

@drowsy kelp

#

obviously you'd have to have the inscribed and circumcircles in the correct place relative to eachother

drowsy kelp
#

Then

#

Can any 2 circles form a triangle, given that one is the "inscribed" and the other one the "circumscribed" one?

rotund willow
#

there will be some constraints on that though

#

but icba to formalise that

#

the issue is that if you have two circles with very close radii then you will end up with angles between lines summing to greater than 180°

#

which obviously can't be a triangle anymore

#

so any 2 circles? no

drowsy kelp
#

Hmm, would the position in space not affect if a triangle is poasible to form, or just the radii?

rotund willow
#

the position would effect it a bit

#

easiest constraint is the inscribed circle must be entirely contained within the circle

drowsy kelp
#

True

rotund willow
#

but even a not similar radius could make it impossible, you see the problem here

#

if they're concentric then there will always be either no possible triangle or an equilateral

#

but that's basic

rotund willow
drowsy kelp
#

CraZy

#

Wish you could remember its name

drowsy kelp
#

+close