#Calculus
18 messages · Page 1 of 1 (latest)
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I got 5/2 for the x value and +- 3.791438 for the two y values
But it says it’s wrong
Got sqrt((x-1)^2+y^2)
Then sqrt((x-1)^2+(20+6x^2/4))
Found d/dx
5x-2
Found 5/2 for the x value as it equals zero
Plugged it in to the original equation and got the 3.79.1438 for y
But it says it’s wrong so idk what I did wrong
wait nvm I see my fuckup
messed up the algebra for finding the zero of 5x-2 = 0
2/5 not 5/2
+close