#How Do I Solve This Question?
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hello yall- i hope yall r able to help me solve this question-
consider abcd
we can see that x = B so we got x = 68
uh huh-
D is equal to 90 so y = 90 - x
the triangle ACD
TD is a tangent so these 2 are equal
wait
yes sir-
and that angle is equal to 180 - D and the angle outside
nani-
we knew D = 90 so we need to find this
what angl-
uh huh
forgive me
i dont get it- we need to find that angle outside?
uh huh-
where do we get 56 again-
the isoceles triangle BAD
angle BAD is (180 - 68) / 2?
also ADT is isoceles too so we found this angle and we can calculate z too
yeah i'm not sure about this cuz i haven't done this kind of geometry for a long time
lemme show u
how is that 56 when the other one is 22
ðŸ˜
EH
ITS TRUE
WAIT ITS WRONG
well just check everything again in case of any mistake
so w is the same as y
both of them r 22?
no
w = this big angle
BAD
y is just a part of it
yeah
180 - 90 - 68
boom 22
well yeah
z is final
DAT is TDA
180 - 68
divided vt 2
by*
wait-
nah nah
how is it 44?1
180 - 68 - 68
:0
44
im so happy rn
ty a lot
@amber widget has given 1 rep to @snow rampart
:D
my native language is not english so i don't know some english words in math
for example alternate segment
vietnamese
Cảm ơn!
im only familiar with some words XD
ty a lot and gud bye
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