#Hey Can I have help with this question?
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EQUATION
Absolute value function looks like this
y = a|x-b| + c
FINDING C
Range is y >= 0, meaning a is positive (the graph goes up) the minimum of the function is 0
Min (|x-b|) = 0 and anything times zero = 0 so Min(a|x-b|) = 0, what do you think c should be so that Min(a|x-b| + c) = 0
FINDING B
The x-intercept is (2/7,0), meaning you have 0 = a|2/7-b|. Since a ≠ 0 (as the function as a whole would equal c) 0 = |2/7-b| meaning 2/7-b = +-0 = 0
FINDING A
You have y intercept as (0,2) once you’ve solved c and b, you can simply solve 2 = a|-b| + c for a
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