#homework help
182 messages · Page 1 of 1 (latest)
you have 2 roots at 0, so x² and one root at 8-3i so x²(x-8+3i) which if you expand out to achieve:
x³-8x²+3ix²
not sure whether it wants real coefficients so that's it
yeah it couldn't want real coefficients
otherwise 8+3i would be listed as a root
hm
would be nice if you told me that it wanted real coefficients? if you knew
Sorry I’m new to all this
you have roots 8-6i,8+6i,0,0,0
so x³(x-8+6i)(x-8-6i)
x³(x²-16x+100)
x⁵-16x⁴+100x³
Imma type it in I’ll let you know if it works
I got it right! Thank you can you help with this one?
you should do the rest yourself, if you have any questions regarding how to do them then ask
I don’t know how to do this math I’m really struggling
@weary rivet can you help me set up the problem and I can work it out?
-6(x+4)²(x-1)
nevermind multiply all of that by -1
Multiply what I got or what your equation is?
yeah if you look at the factored one you'll see I missed a - sign originally
So yours?
so you just multiply everything by -1 and you got the answer
yes, it's right on everything except the factored one I gave you was slightly wrong
So this is the answer?
all you have to do to get the correct answer is do -(6x³+42x²+48x-96)
this was originally 6(x+4)²(x-1)
and that's what you expanded
I got -6x^3-42x^2-48x+96
Oooo I see where I got this wrong
@weary rivet can you help me with graphs?
I struggle with them
@vernal vigil
you should really aim to become independent
I need help
look at the khan academy on graphs
That doesn’t help me
send the graph here and I'll have a look then
Let me see if it works
I can’t check it until the others are filled in
All for the same graph @weary rivet
(-2,-1]
(-∞,-2)∪(-1,∞)
(-∞,-2)∪[-1,∞)
it's up to you now
Please bro
the answer is literally in the graph
I’m off that assignment
Can you help me with rational functions? @chrome scarab
whats the problem
hmm you could break that 11 into 10t and 1t
So what would I type in?
i wont tell you
you need to figure this out
so now we have 2t^2 + 10t + t + 5
factor the first two by 2t
So add them up?
So I factor this?
what would you have if you use the distributive property
Use distributive property on here?
yes
Let me try and work it out please stay
2t^2 + 5*2t + t + 5
can you see what's common
The T?
2t
What now
this
So how would I set up the equation?
use the property
So this?
Like add it up?
I’m so confused
let's take this a step at the time shall we
I’m all for it
you know, a(b + c) = ab + ac, correct?
Yes
So solve this?
2t^2+10t
I got 2t-1 and T-5
like that minus into plus and you're fine
oh no SORRY
had it wrong in my notes haha
Your good I got to this part
yea boy well done
the vertical asymptotes would be whatever value makes the denominator 0
you found those in part2
look at the graph, where do you believe the f(x) leads to as you go to the farthest left***
left sorry
What is the f(x)
the blue line
There’s two blue lines
focus on the one that's on the left, the first one
What do I need to focus on right now for the left line?
imagine that line extend outside of what you see, what kind of value does it approach
0?
Which way is it going?
So what would I type in for that?
3 is my bet
It has to be like formatted as a coordinate I think
oH hold on
Actually nvm it’s just 3
hahaha
aye dont make me sit through all 10 parts
Sorry
as x approaches the value 1 from the left (you can see the black line)
where does the blue line go
you should do a bit more studying mhm
3?
notice how it goes down
you approach 1 from left side
it's like a slidee
therefore?
I get it I got it from here
what would you answer
Idk
It worked!
what worked
The answer is right
ik it's right, did you get it tho?
Yeah
mhm good job
+close