#Enlarge triangle ABC by scale factor -2, centre (4,1)
87 messages · Page 1 of 1 (latest)
- Wait patiently for a helper to come along.
- Once someone helps you, say thank you and close the thread with: ```diff
+close
nhmmmmmmmmmmmmmmmmm
Does this help
(4, 1) is where the lines will pass
and you continue
our base is 1 unit
and height is 2
so by scaling up "-2"
it is twice as bigger and upside sown
How do you know where to place the triangle if it’s twice as big
then what
I guess you multiply with the scale it asks for the both x and y coordinates
take (8 ,1)
My bad
divide
not multiple
8/-2 is -4
hmm
what about for the other coordinates
thats what we are trying to find isnt it
Okay I got an idea
It asks us centre 4, -1
cross that point and
I guess take any point
I will take C
then measure the distance of C from the centre
C (7, -1)
so the distance is 3 along the horizontal and 0 from vertical
now
we took the position C
I will multiply the distances with the same axis
7 x 3 and -1 x 0
that would be the scaled point of the C
oh my bad
hang on
we havent finished yet
after you found these
you will add these numbers
are you available for a vc?
Not really
okay
I am myself trying to solve as well so
ohh I forgot
okay
I am starting with steps
oh
@exotic saddle forget about what I was trying to describe
here a WAAy simple explanation
lets go by A then B then C
A (8, 1)
what is the distance of this from the centre point
same y axis but A is +4 from the point centre we took
now logic is this, if you want to scale something with any number, you multiply the distance with the scale number. However if it's negative scale, then you just simple change the direction on the axis. Let's continue
we found distance is +4
multiply it by -2
we get -8
I did not take the y axis because they are same for the A point
-8 means we will go "-8" units from the centre point
go left from the centre point (4, 1)
we get to (-4, 1)
Do the same to other points
B (6, -1)
distance from (4, 1) is +2 in the x and -2 in the y axis
+2(-2) x and -2(-2) is y axis
-4 from x and 4 from y
why cant I make it simpler
I will now
@exotic saddle just read these below
- If it is negative scale, draw a continuous line from the A B C point to the Centre then continue in the same direction
- Multiply the distances with the scale factor
- Add those distances to centre coordinates and find the scaled positions of the points
please help
uhhhh
create a different topic about this and delete this from here
please
You didn't delete it from here
and delete your messages as well