#Quick Calc Question.

26 messages · Page 1 of 1 (latest)

drowsy bluffBOT
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humble rune
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Yup it's correct

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tan(0)/(1-cos(0)) = 0/0 = indeterminate

last prairie
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2 is also indeterminate

timid relic
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The denominator is 0

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and the top is not

last prairie
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and the numerator is undefined

timid relic
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undefined/0 is not an indeterminate form

humble rune
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The trick here is to first differentiate the function

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And you'll get a quadratic function that needs to be greater than 0

timid relic
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Ye I know how to do it

humble rune
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And by the quadratic formula we know that if the determinant is negative, the equation will have 0 real solutions, so it'll always be postivie

timid relic
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I just wanted answer confirmation for what u think it is

humble rune
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Because we get the determinant is equal to a^2-3b and 30^2-3*301 < 0

timid relic
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Third one doesn't work because at x = 0, we get f'(x) = 0 which can't be the case.

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First 2 have numbers in the negatives

humble rune
timid relic
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Last one works yeah

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will always be larger than 0

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cuz derivative is 3x^2 + 60x + 301

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nice

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I believe it is none of the above

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Can someone confirm?