need help with problem IMPORTANT

[tacit wharf]

Helps

[old scroll]

use Pythagoras to find the height in 1 triangle of the lateral surface area
230/2 = 115
h = sqrt(252²+115²) = ...
Lateral Surface Area
= (1/2)×230×h×4
= ...

[vague pond]

Recall the Pythagoras theorem, and apply it to this shape to find the slant edge triangle's height

$l = \sqrt{252^{2} + (\frac{230}{2})^{2}}$, where l is the slant side triangles' height

[pseudo tree]

Tangerine

[tacit wharf]

Mb

[tacit wharf]

I don’t understand

1/2 times 230 times HEIGHT times 4?

[icy pollen]

lateral surface area of the pyramid is given by
= area of all 4 triangles
= 4 × (area of 1 triangle)
= 4 × ((1/2) × base × height)

[icy pollen]

using the above equation, u can find the value of height of triangle
base of triangle=230 ft (given)

[tacit wharf]

1 sec