You have a stray "|" in line 3, and line 4 is completely wrong; I'm pretty sure you meant eps >= 6/n, therefore n >= 6/eps.
#Is this a good way to pick a value N in a convergence proof?
exotic ibex
fickle vector
What limit do you want to prove
iron moon
Line 2 is also wrong, n² / n³ + 1 <= 1/n³ isn't true for all n
exotic ibex
Line 2 is also wrong, n² / n³ + 1 <= 1/n³ isn't true for all n
Implicitly, this seems to be the limit as n goes to infinity, so for sufficiently large n, it holds.
Or, wait.
Actually, maybe not?
I think it should be n^2/(n^3 + 1) <= 1/n.
worn fjord
Implicitly, this seems to be the limit as `n` goes to infinity, so for sufficien...
Yeah this is going to infinity sorry should have clarified
exotic ibex
Yeah this is going to infinity sorry should have clarified
I mean, what else is an epsilon-N limit supposed to be?
iron moon
1/n³ - n²/(n³+1) < 0 for all n > 1
worn fjord
oh right (I just remembered that my inequality was n^2/n^3+1 <= n^2/n^3 then that got simplified down to n^2/n^3+1 <= 1/n but I omitted that part from the proof. This at least looks good then?)