#Normal vector help
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normal•point on plane
that's a really easy way to extract a normal to a plane from the cartesian
6x-3y+2z=4
(6,-3,2)•(x,y,z)=4
normal is 6,-3,2
modulus of this is √(36+9+4)=√44
so you scale this by 1/√44 and -1/√44 because you can have it both facing above and below the plane
how is √(36+9+4) equal to √44?
so because its a unit vector, it will always be (+/-) <6,-3,2>/√44?
(6,-3,2)/7 yeah
ty!
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