#Help please!
4 messages · Page 1 of 1 (latest)
Write it as $y'-\dfrac{1}{x}y=-9\ln(x)$. The integrating factor is given by $$e^{\int -1/x dx}=x^{-1}$$
Kevin S
I’m not sure how to proceed from there…
4 messages · Page 1 of 1 (latest)
Write it as $y'-\dfrac{1}{x}y=-9\ln(x)$. The integrating factor is given by $$e^{\int -1/x dx}=x^{-1}$$
Kevin S
I’m not sure how to proceed from there…