integration

[coral belfry]

its part b am finding difficulty with

[serene badge]

B

[coral belfry]

am sorry i appreciate the effort but i dont understand what it is you just sent

[serene badge]

@signal shell

[coral belfry]

like what is y=? what function where you integrating in that image

[signal shell]

P(pi/2, 1)
Q(0, h) -> (y-intercept = c)
slope
= m
= (1-h)/((pi/2)-0)
= (1-h)/(pi/2)
= 2(1-h)/pi
= (2-2h)/pi
g(x) = ((2-2h)/pi)x + h
find the intersection of f(x) and g(x) in terms of h, you can find it by equating both equations, i.e. f(x)=g(x), call the point of intersection (a,b), then:
integral from x=0 to x=a of (g(x)-f(x)) dx
= integral from x=a to x=pi/2 of (f(x)-g(x)) dx
then solve for h

[coral belfry]

Thanks i appreciate it i will give it a go and if i get the correct answer i'll let you know

[shut ore]

@coral belfry has given 1 rep to @signal shell

[signal shell]

urwelcome

[coral belfry]

when you get to f(x) =g(x) how do you solve for x

sinx=[(2-2h)/pi]x + h

[signal shell]

hm maybe use wolfram?

,w sin x=[(2-2h)/pi]x+h

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[coral belfry]

i tried didnt really work

maybe i should give chat gpt a go

would this seem correct to you?

i never knew though that an inverse trig function would cancel a normal trig function

[signal shell]

hm not really, x should only be on the LHS but there is still x in the RHS

[coral belfry]

i guess i'll just give up on it

thanks for trying though