#Math Problem

99 messages · Page 1 of 1 (latest)

stable oxide
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okie

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i can help

jaunty tree
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Sweet

stable oxide
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do you want answer or do u want to understand it/ to learn how to do it

jaunty tree
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Answer first then learn

stable oxide
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an exponent is like $5^2$

novel windBOT
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Morphism

jaunty tree
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Right

stable oxide
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do you how what that is

jaunty tree
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Yes

stable oxide
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so 5^2 = 25

jaunty tree
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Right

coral coyote
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How do you do subscripts here for log bases?

jaunty tree
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Idk

stable oxide
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when you do log, you are trying to do something like this

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$5^x = 25$

novel windBOT
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Morphism

stable oxide
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where you wanna solve for x

jaunty tree
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I dont follow that last part

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What does $ mean?

stable oxide
coral coyote
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Okay, so the relationship between log and exp is like that of division and multiplication.

jaunty tree
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Ok...

stable oxide
jaunty tree
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Squared

stable oxide
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YES ok

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you understand

coral coyote
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So if a/b = c that means a = bc.

jaunty tree
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But whats log then?

stable oxide
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that is basically the whole idea behind log

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wait 1 sec

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xd

jaunty tree
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Sorry

stable oxide
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1 minute

coral coyote
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Log is the reverse of exp. So log_a(a^b) = b.

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and a^(log_a(b)) = b.

stable oxide
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ok

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no

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you are asking this

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729^(-5/6) = x

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solve for x

coral coyote
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Take your equation log_729(a) = -5/6.

stable oxide
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i probably confused u :P

coral coyote
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that means that 729^(log_729(x)) = 729^(-5/6).

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and the lhs of that is x.

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so x = 729^(-5/6).

stable oxide
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@jaunty tree refer to the image that i sent.
Log_729(x) = -5/6
means
729^(-5/6) = x

jaunty tree
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So what is 729^(-5/6)

stable oxide
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lol

jaunty tree
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I dont get how you go from 729^

stable oxide
jaunty tree
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Is ^ sq rt?

stable oxide
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nop

jaunty tree
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so 27?

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:l

stable oxide
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the answer to your problem is 1/243

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:P

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^ isn't sqrt

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^ is exponent

jaunty tree
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Then how do you know what the exponent is?

stable oxide
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do u see the image i sent here

coral coyote
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3^6 = 729

jaunty tree
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@stable oxide sorry I don't follow that at all 😭

coral coyote
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729^(-5/6) = 1/(729^(5/6)) = 1/3^5 = 1/243.

stable oxide
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1 sec CP

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ima draw it using a picture

jaunty tree
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Ok tysm

stable oxide
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ok

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ill make it simple

coral coyote
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All you need to solve it is calculator with a square root key. First lets get the sixth root of 729.

stable oxide
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remember the one with 5 squared?

coral coyote
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729^1/6 = (729^(1/2))^(1/3).

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sqrt(729) = 27.

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and the cube root of that is 3 because 3^3 = 27.

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so now we want 3^5. And that's 243.

stable oxide
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@jaunty tree

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does it make sense with the 5 example

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:P

jaunty tree
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Maybe?

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Phew, I need Taco Bell XD

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But

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I think I got what I needed

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Thanks guys

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My teacher says he'll disect it with me tmrw

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But yes, I think it makes sense

stable oxide
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type in 1/243 for your answer :P

jaunty tree
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Ok tysm

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That'll get me by

coral coyote
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CP137 are you familiar with f(x) notation?

stable oxide
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she probably will be even more confused Pug lol

rocky latch
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@jaunty tree can you remove the image from your post please

jaunty tree
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How?

rocky latch
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If you cant I'll delete it

coral coyote
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Think of f(x) = log_a(x) as a machine that takes a number and gives you a number and think of g(x) = a^x the same way.

rocky latch
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Sorry have to remove this

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Continue somewhere else please

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Or well