#Math Problem
99 messages · Page 1 of 1 (latest)
Sweet
do you want answer or do u want to understand it/ to learn how to do it
Answer first then learn
an exponent is like $5^2$
Morphism
Right
do you how what that is
Yes
so 5^2 = 25
Right
How do you do subscripts here for log bases?
Idk
Morphism
where you wanna solve for x
that is latex i tried to make the image you see right there :P
Okay, so the relationship between log and exp is like that of division and multiplication.
Ok...
what do you need to raise 5 to, to get 25?
Squared
So if a/b = c that means a = bc.
But whats log then?
Sorry
1 minute
Take your equation log_729(a) = -5/6.
that means that 729^(log_729(x)) = 729^(-5/6).
and the lhs of that is x.
so x = 729^(-5/6).
@jaunty tree refer to the image that i sent.
Log_729(x) = -5/6
means
729^(-5/6) = x
So what is 729^(-5/6)
lol
I dont get how you go from 729^
Is ^ sq rt?
nop
Then how do you know what the exponent is?
do u see the image i sent here
3^6 = 729
@stable oxide sorry I don't follow that at all ðŸ˜
729^(-5/6) = 1/(729^(5/6)) = 1/3^5 = 1/243.
Ok tysm
All you need to solve it is calculator with a square root key. First lets get the sixth root of 729.
remember the one with 5 squared?
729^1/6 = (729^(1/2))^(1/3).
sqrt(729) = 27.
and the cube root of that is 3 because 3^3 = 27.
so now we want 3^5. And that's 243.
Maybe?
Phew, I need Taco Bell XD
But
I think I got what I needed
Thanks guys
My teacher says he'll disect it with me tmrw
But yes, I think it makes sense
type in 1/243 for your answer :P
CP137 are you familiar with f(x) notation?
she probably will be even more confused Pug lol
@jaunty tree can you remove the image from your post please
How?
If you cant I'll delete it
Think of f(x) = log_a(x) as a machine that takes a number and gives you a number and think of g(x) = a^x the same way.