#double factorial question
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(2m)!! = 2*4*...*(2m - 2)*(2m) = (2*1)(2*2)...(2(m - 1))(2m) = 2^m (1*2*...*(m - 1)*m) = 2^m m!
2 messages · Page 1 of 1 (latest)
m is a positive integer
(2m)!! = 2*4*...*(2m - 2)*(2m) = (2*1)(2*2)...(2(m - 1))(2m) = 2^m (1*2*...*(m - 1)*m) = 2^m m!