#algebra/ logs
18 messages · Page 1 of 1 (latest)
,rotate
Yes
Damn is the working out that long
alpha^(n + 1)
= alpha^n * alpha
= (a * alpha + b) * alpha
= a * alpha² + alpha * b
= (a * alpha)alpha + alpha * b
c = a * alpha
d = b * alpha
cd = ab * alpha²
cd/ab = alpha²
alpha^(n + 3)
= alpha^(n + 1) * alpha²
= (c * alpha + d) * cd/ab
= (c²d/ab) * alpha + cd²/ab
I just got it till here
Wait
But isn’t
It a * alpha
Since bracket expansion
which part?
cuz cd = ab * alpha²
Wait