functions quick

[mystic tulip]

Help

[lilac trout]

First, it would be better to simplify f(x) a bit first:
f(x) = (x - 3)/(2x) = 1/2 - 3/(2x)
Then find f(x + 1) and f(2x). After that, solve the equation.

[fickle thicket]

so you start by substituting in X+1 for x
(x+1-3)/(2x+2) and then you substitute in 2x for x
(2x-3)/4x
(x-2)/(2x+2)-(2x-3)/4x=0.5

[mystic tulip]

Wait so do I just add 1 to the f(x)

Then on another one do 2x

[lilac trout]

No.

Don't confuse f(x + 1) with f(x) + 1.

[mystic tulip]

Aren’t they only different on graphs

[lilac trout]

Of course not.

Well, we have f(x) = 1/2 - 3/(2x).
What is f(x + 1)?

[mystic tulip]

(1/2 - 3/(2x)) + 1

[lilac trout]

No, that is f(x) + 1.

[mystic tulip]

Oh

[fickle thicket]

you can add f(1)

[lilac trout]

What? No.

[fickle thicket]

lmao

f(X+1)=f(x)+f(1) obviously

[lilac trout]

No.

f(x) is not linear here.

[fickle thicket]

algebra is a lie smh

[lilac trout]

Not a good place to joke like that.

[fickle thicket]

fine

[mystic tulip]

x-3+1/2x+1

?

[lilac trout]

What? Where did that come from?

[mystic tulip]

I just added one to top and bottom

[lilac trout]

No.

To find f(x + 1), you need to replace x by (x + 1) in the expression of f(x).