#Thread
7 messages · Page 1 of 1 (latest)
do you mean ⅙log(1512) + ⅙log(7)?
no like uhh
ik i need to multiply 1512 and 7 but idfk what to do next with -log6(10584)
yes that's exactly what I meant
leave it as it is
7 messages · Page 1 of 1 (latest)
log(1/6)1512 + log(1/6)7
do you mean ⅙log(1512) + ⅙log(7)?
no like uhh
ik i need to multiply 1512 and 7 but idfk what to do next with -log6(10584)
yes that's exactly what I meant
leave it as it is