#How to find points of differentiability of this function?
11 messages · Page 1 of 1 (latest)
Well, |x| is differentiable everywhere except x = 0.
Thus, the only points in question are x = 1 and x = 3.
Oh so even at x=3?
Well, spoiler: x = 3 is fine. But you still need to make sure 😁
It's (x-3)^3
Unless you prove a more general result, of course.
Mhmmm
What about this one? Haha
Oh, sorry, didn't notice your solution.
Yeah, that works.