I just wanted to get it confirmed, is 2b i)
(a, b, c) = (20/7, 65/7, 40)?
#Correct answer/s?
delicate cedar
I just wanted to get it confirmed, is 2b i)
(a, b, c) = (20/7, 65/7, 40)?
No, doesn't seem to be correct.
willow osprey
my previous answer was 2,5 7,5 and 30. But now I got tose answers above. Im confused
willow osprey
No, doesn't seem to be correct.
nevermind lol, I made a typo in symbolab.
delicate cedar
Oh, ok.
willow osprey
c was quite easy with gauss/cramers, shame it isntallowed. If you want to, how do I do this with elimination method?
delicate cedar
Wait, why is Gauss not allowed?
willow osprey
I mulriplied the denominator to get rid of it on the left
delicate cedar
That's kinda dumb.
Hm, let's see.
4x^3 + x^2 + 16x + 15 = (ax + b)(x^2 + 2x + 5) + (cx + d)(x^2 + 1)
What did you get when you simplified the right part?
willow osprey
That's kinda dumb.
"the crowd" wont understand it as we havnt learned it"
crowd implying the other students
willow osprey
lol dont ask me, I can use elimination or subtraction
delicate cedar
I mean, solving systems with 4 or more equations without Gauss is reeeeeally painful.
willow osprey
I showed him matrices and he said no re-do it
delicate cedar
Ugh... That sucks. Oh well...
What is the system that you got?
willow osprey
Hm, let's see.
4x^3 + x^2 + 16x + 15 = (ax + b)(x^2 + 2x + 5) + (cx + d)(x^2 + 1...
(a+c)x^3 + (b+2a+d)x^2 + (2b+5a+c)x + (5b+d) on the right
delicate cedar
(a+c)x^3 + (b+2a+d)x^2 + (2b+5a+c)x + (5b+d) on the right
Yeah, seems good. And the system?
willow osprey
5b+d = 15
5a+2b+c = 16
2a + b + d = 1
a + c = 4
delicate cedar
Yeah, seems good. Well, now let's try solving it...
First, express c from the fourth equation and substitute it into the other three (well, really, only into the second).
delicate cedar
which I got with cramers lol but anyway
Oh...
Well, alright. Though, doing Cramer for this probably takes 3 years.