help

[rain condor]

@everyone can anyone help?

[alpine drum]

a) see the value of h(t) when t = 6
b) see the value of t when h(t) = 0
c) h^-1(t) is the inverse function
h(t), meaning you swap the x
and y values, for example in
the given when t = 0, h(t) = 6,
now swap it, becomes when
t = 6, h^-1(t) = 0
d) see the value of t when
h^-1(t) = 1

[rain condor]

is this the answer?

[alpine drum]

no that's just the explanation